PT-2026-61301 · Linux · Linux
CVE-2026-63984
·
Publicado
2026-07-19
·
Atualizado
2026-07-19
CVSS v3.1
9.8
Crítica
| Vetor | AV:N/AC:L/PR:N/UI:N/S:U/C:H/I:H/A:H |
In the Linux kernel, the following vulnerability has been resolved:
ipv6: rpl: fix hdrlen overflow in ipv6 rpl srh decompress()
ipv6 rpl srh decompress() computes:
outhdr->hdrlen = (((n + 1) * sizeof(struct in6 addr)) >> 3);
hdrlen is u8. For n >= 127 the result exceeds 255 and silently
truncates. With n=127 (cmpri=15, cmpre=15, pad=0, hdrlen=16):
(128 * 16) >> 3 = 256, truncated to 0 as u8
The caller in ipv6 rpl srh rcv() then places the compressed header
at buf + ((ohdr->hdrlen + 1) << 3). With hdrlen=0 this is buf + 8,
but the decompressed region occupies buf[0..2055] (8-byte header
plus 128 full addresses). The compressed header overlaps the
decompressed data, and ipv6 rpl srh compress() writes into this
overlap, corrupting the routing header of the forwarded packet.
The existing guard at exthdrs.c:546 checks (n + 1) > 255, which
prevents n+1 from overflowing unsigned char (the segments left
field), but does not prevent the computed hdrlen from overflowing
u8. n=127 passes because 128 <= 255, yet hdrlen=256 does not
fit.
Tighten the bound to (n + 1) > 127. This caps n at 126, giving
hdrlen = (127 * 16) >> 3 = 254, which fits in u8. The compressed
header then lands at buf + ((254 + 1) << 3) = buf + 2040, exactly
past the decompressed region (buf[0..2039]). No overlap. 127
segments is well beyond any realistic RPL deployment.
Correção
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